Electromagnetic induction — moving a magnet into a coil
"If we move the magnet into the coil there's going to be a current that's generated in the coil. This current is going to move in the counterclockwise direction. The magnet produces a magnetic field which goes into the page."
"If we move it away from the coil then the direction of the current will reverse. If you move the magnet slowly into the coil the induced current will be very small, but if you move the magnet quickly the induced current will be larger."
"If you don't move the magnet into the coil there will be no induced current. So it also depends on the speed at which the magnet moves into or out of the coil: the greater the speed, the greater the induced current will be."
"The magnet produces a magnetic field which goes into the page. X represents into the page and a circle represents out of the page."
Lenz's Law walk-through — magnet in
- Φ is increasing (magnet getting closer → more flux through coil)
- External B is into the page (field lines leave N pole)
- Induced B must oppose → points out of the page inside the loop
- By right-hand rule, induced I flows counterclockwise
In 1831, Michael Faraday did exactly this experiment: he pushed a bar magnet into a coil of wire and watched a galvanometer needle deflect. It was the first time anyone had ever seen electricity created from magnetism using only motion. Every generator in the world — from the alternator in your car to the turbines at a nuclear power plant — traces back to this one observation.
What's actually happening at the atomic level: the magnet carries a cloud of magnetic field lines. As you push it toward the coil, more and more of those lines start to thread through the wire loop. A moving magnetic field exerts a sideways force on the free electrons in the copper wire (via the Lorentz force), and that sideways push sets them flowing around the loop. That circulating motion is the induced current.
Three crucial observations from the demo:
- Motion is required. Holding the magnet still inside the coil → no current. Induction only cares about change.
- Reversing motion reverses current. Pushing in vs. pulling out flips the induced current's direction.
- Speed matters. Moving faster generates a larger current because the flux is changing at a higher rate (dΦ/dt is bigger).
Tie to later slides: everything in this deck — Lenz's Law, Faraday's Law, generators, transformers, inductors — is just bookkeeping on top of this one phenomenon. Keep this picture in your head and the rest is dressing.
Magnetic flux — Φ = B·A·cos θ
"The magnetic flux is equal to the product of the magnetic field times the area times cosine of the angle, and the unit for magnetic flux is the Weber. One Weber is basically one Tesla times one square meter."
"θ is the angle between the normal line and the magnetic field. The electric flux is greatest when the magnetic field is parallel to the normal line, or when it's perpendicular to the face of the coil."
"There are other ways to induce a current, and it's not only just moving the magnet into or out of the coil. If you change the area of the coil — let's say if you stretch it or bend it — that will induce a current also. If you change the angle of the coil relative to the magnetic field, an induced current will be created."
"If the magnetic field doesn't pass through the face of the coil — if it's parallel to the face of the coil — there will be no electric flux, and if there's no electric flux there's no induced EMF."
"If the magnetic field is parallel to the normal line, so the magnetic field is perpendicular to the plane of the coil, the angle θ is zero, and cosine zero is equal to one, so the electric flux is simply equal to B times A."
Three ways to induce an EMF
- Change the magnetic field B (move a magnet, switch a current on/off)
- Change the area A of the loop (stretch, shrink, or sweep)
- Change the angle θ between B and the loop normal (rotate the coil)
Magnetic flux Φ is not a thing you can touch — it's a count of how many magnetic field lines pass through a surface. Imagine field lines as invisible arrows; flux measures how many thread through your loop. More arrows = more flux. The unit is the Weber, where 1 Wb = 1 T·m².
Why the cosine? If the loop faces the field head-on (θ = 0°, normal parallel to B), every field line passes through it → maximum flux, BA. Tilt the loop 90° so it's edge-on to the field (θ = 90°) → the field lines slide past without crossing the loop → zero flux. The cosine smoothly interpolates between these extremes: cos 0° = 1 (max), cos 90° = 0 (none), cos 60° = 0.5 (half).
Always measure θ from the NORMAL, not from the loop's face. This is the #1 source of mistakes. The "normal vector" sticks straight out perpendicular to the loop's surface like a little flag on the coil's face. The angle you want is between this flag and the direction of B.
Only three knobs exist: Φ = B·A·cos θ has exactly three variables, so only three things can possibly induce an EMF — changing B, A, or θ. Every induction problem in this course is one of these three. If you can identify which knob is turning, you've already done half the work.
Faraday's Law — ε = −N · ΔΦ/Δt
"The induced EMF is equal to N times the change in the electric flux divided by the change in time. This equation is associated with Faraday's law of induction. If you have 10 loops compared to one loop, the induced EMF and therefore the induced current will be larger."
"If you take your right hand and wrap it around a pen and you want your thumb to face the direction of the current, the way your fingers curl around the pen is the direction of the magnetic field as it travels around the conductor."
"The induced EMF and therefore the induced current is dependent on the rate of change of the magnetic flux."
"The induced EMF you can treat it like voltage. Voltage and EMF both have the same unit — the volt. So if V is equal to I times R, then the induced EMF is equal to I times R. If you know the induced EMF and the resistance, you can calculate the induced current."
Connecting ε to induced current
- Induced EMF behaves like a voltage (unit: volts)
- Iinduced = ε / R — if ε doubles, I doubles (R is fixed)
- ε depends on the rate of change of Φ, not the value of Φ itself
Faraday's Law is the most important equation in this unit, and the thing students miss most often is this: a large flux produces zero EMF if it isn't changing. A powerful magnet sitting motionless next to a coil induces nothing. The EMF depends only on how fast the flux changes — ΔΦ/Δt — not on how much flux there is.
The anatomy of ε = −N·ΔΦ/Δt:
N= number of turns in the coil. Double the turns → double the EMF. This is why coils have so many windings.ΔΦ= change in flux per turn = Φ_final − Φ_initial (in Webers, Wb)Δt= time over which that change happens (in seconds)−= Lenz's Law sign; nature opposes the change
Why N multiplies: each turn of the coil is its own little loop, and each loop sees the same ΔΦ/Δt. The EMFs add in series like batteries stacked end-to-end, so total EMF = N × (EMF per turn). A 1000-turn coil generates 1000× more voltage than a single turn in the same field change.
Units check: [Wb/s] = [T·m²/s] = [V]. Weber per second is volts. Faraday's constant (−1) just carries the direction.
Lenz's Law — the 4-step walk-through
"Lenz's law states that the induced EMF always gives rise to a current whose magnetic field opposes the original change in flux. Since the external magnetic field is increasing, the induced current will create a magnetic field that will oppose the external magnetic field."
"If the flux increases the induced current will be directed in such a way to decrease the flux. So if you try to increase the flux, the induced current will oppose that change — it's going to decrease it. And if you try to decrease the flux, the induced current will try to support it or increase it. So it's always opposite to what you're trying to do."
"The magnetic field emanates away from the North Pole and enters the South Pole, so the magnetic field is going into the page. That's the external magnetic field. The external magnetic field is directed into the page, so if the induced field is going to oppose it, it has to be out of the page."
The 4-step method — memorize this
- Is Φ increasing or decreasing?
- Which direction is the external B?
- Induced B must oppose the change (opposite to ΔB)
- Apply the right-hand rule to get induced current direction
Students get Lenz wrong constantly because they say "the induced field opposes the external field." That's not quite right. The induced field opposes the change in flux — not the field itself.
Example to see the difference: suppose B points into the page and is growing stronger. Induced B points out of the page (opposing the increase). Now suppose B points into the page and is getting weaker. Induced B points into the page (supporting the dying field). In both cases the external B is "into the page," but the induced B points opposite directions — because in one case Φ is rising, in the other it's falling.
Memory aid — the bar-magnet push test: push the north pole of a magnet toward a loop. The loop "sees" an approaching N pole and doesn't want it, so it induces a current that makes the loop itself act like a north pole facing the magnet (so N–N repels). Pull the magnet away? The loop makes itself a south pole to attract it back. The loop is always fighting the change.
Right-hand rule for the induced current: once you know which way the induced B points, curl the fingers of your right hand in that direction inside the loop. Your thumb gives the current direction. Practice this until it's automatic — Lenz problems become trivial.
Lenz examples — moving and shrinking loops
"The magnetic field is constant, however the area inside the rectangular loop that is exposed to the magnetic field is increasing, so the magnetic flux is increasing."
"The external magnetic field is constant but the rectangular loop is moving away from the magnetic field, therefore the area exposed to the magnetic field is decreasing, so the flux is decreasing."
"Because the area is decreasing, the magnetic flux is decreasing as well. If the flux is decreasing, according to Lenz's law, the induced current will try to increase the flux, which means that it's going to create an induced magnetic field that is in the same direction as the external magnetic field."
"As the coil moves into the magnetic field, the current travels in the counterclockwise direction, and as it moves away from the magnetic field, it's going to reverse and travel in a clockwise direction."
Pattern — when flux DECREASES into the page
- Φ is decreasing (less area or less B)
- Induced current wants to support the dying field
- So B_ind is in the same direction as B_ext (into page)
- RHR gives induced I flowing clockwise
The key insight of Lenz's Law: the induced current always fights whatever you're doing. Push a magnet in? Current flows to push back. Pull it out? Current flows to pull it back. Shrink the loop? Current flows to support the dying field. The universe, essentially, does not like change.
Why it must be this way — energy conservation. Imagine Lenz's Law were backwards and induced currents helped the change. Push a magnet in → current creates a field that pulls it in harder → magnet accelerates → stronger change → more current → more pull — a runaway loop producing infinite energy from nothing. That's impossible, so Lenz must oppose. The minus sign in Faraday's law isn't a convention; it's thermodynamics.
The two patterns to memorize (everything else is just variations):
- Φ increasing some direction → B_induced points the opposite way → fingers of right hand curl that way → thumb gives current direction
- Φ decreasing some direction → B_induced points the same way (to support) → same RHR trick
Test yourself: a loop sits in a B field pointing out of the page. The field is being turned off. Which way does induced current flow? (Answer: CCW — it tries to keep the outward flux alive.)
Lenz examples — wire + loop coupling
"If the current in a straight wire is increasing, then the magnetic field is increasing, which means the flux generated by that wire is increasing. The induced current in the circular wire is going to create a flux that opposes the original flux."
"Once we close the switch the current will go from 0 to 2 amps, so the current is increasing, which means that the flux is increasing. The induced current will try to oppose the change in flux."
"If the current is going to the left and that current is decreasing, the external magnetic field is out of the page below the wire. The flux is decreasing because the current is decreasing. A decreasing current will produce a decrease in magnetic field, and a decrease in magnetic field leads to a decrease in flux."
"Anytime the induced current tries to increase the flux, it's trying to support the decreasing magnetic field, and anytime it wishes to support it, the two magnetic fields have to be in the same direction."
Everything we've seen so far involved motion — a magnet moving, a rod sliding, a coil shrinking. But these examples show induction happening with nothing moving at all. Just a current changing in one wire produces a voltage in a completely separate circuit nearby. This is mutual induction, and it's how wireless chargers and RFID tags work.
The chain: changing I in wire 1 → changing B field in space → changing flux Φ through loop 2 → induced EMF in loop 2 (via Faraday) → induced current in loop 2 (which by Lenz opposes the flux change).
Which way does induced current flow? Use Lenz's 4-step walk-through:
- Closing the switch → outer current ramps up from 0 → Φ through inner loop grows
- Outer current CCW → B (by RHR curl) points out of page inside the inner loop → Φ_ext is increasing out of page
- Inner loop opposes increase → its induced B must point into page
- RHR: fingers curling into page means thumb points to a CW current → inner I is clockwise
The induction is transient. Once the switch has been closed for a while and the outer current is steady, dI/dt = 0, so the induced current in the inner loop dies. You only get induction while something is changing.
Problem 1 — Changing magnetic field in a single loop
"A single circular loop of wire is perpendicular to a magnetic field which increases from 1.5 Tesla to 4.8 Tesla in 23 milliseconds."
"The magnetic field is perpendicular to the circular loop, which means that it's parallel to the normal line. So the angle θ is the angle between the normal line and the magnetic field — therefore the angle is 0°, and cosine of 0 is 1."
"The induced EMF is N times the change in flux divided by the change in time. N is the number of loops, and we have a single circular loop, so N is 1."
Given
- N = 1 loop, r = 25 cm = 0.25 m
- B: 1.5 T → 4.8 T, Δt = 23 ms = 0.023 s
- Angle: B ⊥ to plane → θ = 0° between B and n̂, so cos θ = 1
- R = 20 Ω (for part C)
Every Faraday problem — no matter how it's worded — boils down to three questions. Answer them in order and you can solve any of these:
- What's changing? B, A, or θ? Only one (usually) is changing; the rest are constants.
- What's ΔΦ? Compute Φ_final − Φ_initial. Keep B, A, cos θ that don't change outside the subtraction.
- Plug into ε = −N·ΔΦ/Δt. The N is the number of loops, not turns per meter.
This problem: the B field changed (not A, not θ), so ΔΦ = ΔB · A · cos θ. With A = π(0.135)² and ΔB = 11.32 T, we get 0.648 Wb per turn. One loop only (N=1), so ε = 0.648/0.023 ≈ 28 V. Then Ohm's Law gives I = ε/R.
Once you have ε, the circuit just obeys Ohm: the induced EMF behaves exactly like a battery. Current is ε/R, power is εI = ε²/R, and Lenz's Law only tells you direction — not magnitude.
Problems 2 & 3 — Flux reversal and stretching coil
Problem 2 — Flux reverses sign
- N = 20 loops
- Φ: +2 Wb → −3 Wb in 425 ms
- I = 5.12 A (measured)
ε = −N·ΔΦ/Δt = −20·(−5)/0.425
ε ≈ 235.3 V
R = ε/I = 235.3/5.12 ≈ 46 Ω
P = ε·I ≈ 1205 W
Problem 3 — Stretching rectangular coil
- N = 150 loops
- 5×8 cm² → 7×11 cm² in 0.15 s
- B = 2.5 T, 30° to the plane → θ to normal = 60°
- R = 100 Ω (for part B)
ε = −N·B·ΔA·cos 60° / Δt
= −(150)(2.5)(0.0037)(0.5)/0.15
ε ≈ −46.25 V
I = |ε|/R = 0.4625 A
W = P·Δt = (|ε|·I)(0.15) ≈ 3.21 J
"The magnetic field is 30° relative to the plane of the coil, but θ is the angle between the normal line and the magnetic field, so θ in this problem is 60 — it's 90 minus 30."
"The magnetic flux through a coil of wire containing 20 loops changes from 0.2 to −0.3 Webers in 425 milliseconds. What is the induced EMF?"
"A flexible rectangular coil of wire with 150 loops is stretched in such a way that its dimensions change from 5 by 8 square cm to 7 by 11 square cm in 0.15 seconds, in a magnetic field of 2.5 Tesla that is 30° relative to the plane of the coil. Calculate the induced EMF."
"How much energy in Joules was dissipated in the circuit if the total resistance is 100 ohms? Before we can find the energy we need to calculate the power, and before we can find that we need to find the current."
Trap #1 — Flux reversal. If a loop starts with flux +0.50 Wb pointing up and ends with flux −0.50 Wb (pointing down), the change is not zero — it's ΔΦ = −0.50 − (+0.50) = −1.00 Wb. The field had to pass through zero and go the other way. Students commonly write ΔΦ = 0 here; that's a 50-point mistake.
Trap #2 — Stretching changes area. If you pull a coil so its width increases from w₁ to w₂ while height stays fixed, ΔA = h·(w₂ − w₁). The B field never changed; only A did. Same Faraday equation, different variable inside the Δ.
Trap #3 — "30° to the plane" ≠ θ for the formula. The angle in Φ = BA·cos θ is always measured from the normal to the loop surface, not from the loop's face. "30° above the plane" means θ = 90° − 30° = 60° from the normal. Draw the normal first, always.
Why the sign of ε matters: the minus in Faraday's law is Lenz's Law in disguise. If you get a positive ε, the induced current flows one way; negative ε means it flows the opposite way. For magnitudes (which problems usually ask for), just take the absolute value — but the sign carries the physics of "opposition."
Problem 4 — Angle change in a rectangular coil
"A rectangular coil of wire contains 25 loops. The angle between a normal line of the coil and the magnetic field changes from 70 to 30° in 85 milliseconds. Calculate the induced EMF."
"There are two ways the angle could change: either the magnetic field is constant and the coil changes relative to the magnetic field, or the coil is held in place and the magnetic field changes direction relative to the coil. In this problem it really doesn't matter which one changes — all we need to know is the final angle and the initial angle."
"The magnetic field B is constant, the area is constant, but the angle changes, so it's going to be B times A times the change in cosine θ divided by Δt."
Given
- N = 25 loops, B = 3 T (constant)
- Area = 15 cm × 20 cm = 0.15 × 0.20 = 0.03 m² (constant)
- θ: 70° → 30°, Δt = 85 ms = 0.085 s
- Only cos θ changes → pull B and A out of Δ
Flux is Φ = BA·cos θ, which means there are three ways to change it: change B, change A, or change θ. Any one of them produces an EMF. Which one a problem uses tells you which variable goes inside the Δ — and which ones come outside as constants.
This problem: B is constant (3 T), A is constant (0.03 m²), only the angle rotates from 70° → 30°. So ΔΦ = B·A·(cos 30° − cos 70°). The B and A come out of the Δ because they don't change. Only the cos term gets subtracted.
Common mistake: students compute Δθ = 40° and try to put it inside the cosine as "cos(40°)". That's wrong — you must evaluate cos at the two angles separately and subtract: cos(θ_f) − cos(θ_i).
Why the sign is negative: going from 70° to 30° means the normal is rotating to align more with B, so flux is increasing (cos 30° > cos 70°). By Lenz's Law, the induced EMF opposes this growth — hence the minus sign. The magnitude is what matters for the numeric answer; the sign just tells you which direction current flows.
Motional EMF — ε = B·L·v (rod on rails)
"As the rod moves towards the right, the area is increasing, which means the flux is increasing. The change in area is L times d, and d is the velocity times the change in time, so the induced EMF is B · L · v."
"Turns out that there's another way in which we could derive that same equation. The magnetic force on a moving charge is BqV. The electrons move a distance L, the length of the rod. Notice that Q cancels, and we get the same formula: the induced EMF is equal to the magnetic field times the length of the moving rod times the speed of the moving rod."
"A moving rod 45 cm long slides to the right with a speed of 2 m/s in a magnetic field of 8 Tesla. What is the induced EMF?"
"What force is required to keep the rod moving to the right at a constant speed of 2 m/s? The magnetic force that acts on a wire with a current is equal to I·L·B·sin θ. Because the magnetic field is perpendicular to the area of the rectangular coil, sin 90° is 1, so we just multiply those three values."
Two equivalent derivations of ε = BLv
- Faraday route: ΔA = L·v·Δt, so ΔΦ = B·L·v·Δt, therefore ε = ΔΦ/Δt = BLv
- Lorentz route: force on charges in rod is F = qvB; work done moving charge across L is W = qvBL; ε = W/q = BLv
- Force to maintain motion: F = BIL (because the induced current experiences a magnetic force opposing v)
Motional EMF is a real battery made of nothing but a moving wire in a magnetic field. Here's what's happening at the particle level: the rod contains free electrons. When the rod moves with velocity v through a field B, each electron feels the Lorentz force F = qv×B. This force pushes electrons along the length of the rod, piling them up at one end.
The pile-up creates an electric field inside the rod, which eventually balances the magnetic force. At equilibrium, one end of the rod is at higher potential than the other — by exactly ε = BLv volts. That's a voltage source, identical from the outside to a battery.
Where does the energy come from? You do! To keep the rod moving at constant v against the magnetic drag force F = BIL, you must push with an equal external force. The power you supply, P = F·v = BIL·v = (BLv)·I = εI, equals the electrical power dissipated in the resistor. Mechanical work in = electrical energy out. This is the underlying principle of every generator — from a bicycle dynamo to a 500-ton turbine at a hydro dam.
Two paths, one answer: the Faraday derivation (flux sweeping out area) and the Lorentz derivation (force on charges) give the exact same ε = BLv. Physics is self-consistent like that — two totally different approaches land on identical predictions.
AC Generator — εmax = N·B·A·ω
"The induced EMF of a generator is equal to N times B times A times ω times sin(ωt). To find angular velocity ω, it's simply equal to 2πf, where f is the frequency measured in hertz."
"A 60 Hz AC generator rotates in a 0.25 Tesla magnetic field. The generator consists of a circular coil of radius 10 cm with 100 loops. What is the angular velocity and calculate the induced EMF?"
"The angular velocity and the induced EMF are proportional. If you increase the angular velocity, the EMF will increase — they're directly related. So if you double the number of RPM, the induced voltage will double as well."
"A generator produces an EMF of 12 volts at 700 RPM. What is the induced EMF of the generator at an angular velocity of 2400 RPM?"
Problem 6 — numbers
- f = 60 Hz, B = 0.25 T
- r = 10 cm → A = π(0.1)² = 0.0314 m²
- N = 100 loops
- ω = 2π(60) = 376.99 rad/s
- ε_max = NBAω = 29.61 V
Problem 7 — scaling with RPM
- "A generator produces 12 V at 700 RPM. Find ε at 2400 RPM."
- Since N, B, A are fixed, ε ∝ ω ∝ RPM
- ε₂/ε₁ = 2400/700 ≈ 3.429
- ε₂ = 12 · 3.429 = 41.1 V
A generator is just a rotating coil in a magnetic field. As the coil spins, the angle θ between the loop's normal vector and B changes continuously: θ = ωt. So the flux through the loop is Φ = BA·cos(ωt) — a cosine that oscillates between +BA and −BA.
Where the sine comes from: Faraday says EMF = −N·dΦ/dt. Take the derivative of cos(ωt) and you get −ω·sin(ωt). So ε(t) = NBAω·sin(ωt). The peak value is ε_max = NBAω — that's where the formula comes from. It's not memorization; it's calculus meeting geometry.
Why AC is sinusoidal: every wall outlet in your house runs on this equation. In the US, ω = 2π·60 Hz ≈ 377 rad/s, which is why the peak voltage is ~170 V (and the RMS value — the "effective" DC-equivalent — is 120 V).
Why faster = bigger voltage: spinning the coil twice as fast doubles ω, which doubles both the rate of flux change AND the angular frequency. So ε_max scales linearly with RPM. A 700-RPM generator at 2400 RPM puts out exactly 2400/700 = 3.43× more voltage.
Transformers — VP/VS = NP/NS
"A transformer is made up of two sets of coils wrapped around an iron core. Because the secondary coil has more turns than the primary, this is going to be a step-up transformer. When the voltage goes up, the current goes down such that the power is the same."
"Energy is conserved. The amount of energy that's being transferred on the left side should be equal to the energy being transferred out of the right side. The amount of energy that is going into the system should equal the amount of energy coming out of the system for an ideal transformer."
"Most real-life transformers are about 99% efficient. Percent efficiency is equal to the output power divided by the input power times 100%. The output power can only be equal to or less than the input power — it cannot be more."
"The equations that you need for transformers are NS over NP equals VS over VP equals IP over IS. And the power is voltage times current: VS times IS is equal to VP times IP if it's 100% efficient."
"A transformer has 50 primary turns and 400 secondary turns. The input voltage is 12 volts and the input current is 24 amps. What is the voltage and current at the secondary coil, and how much power is consumed by the primary coil?"
Problem 8 — step-up transformer walk-through
- Ratio N_S/N_P = 400/50 = 8 → step-up
- V_S = V_P · (N_S/N_P) = 12 · 8 = 96 V
- I_S = I_P · (N_P/N_S) = 24 / 8 = 3 A
- P = V_P·I_P = 12·24 = 288 W = V_S·I_S (energy conservation)
A transformer has no electrical connection between its two sides. Current on the primary side never crosses into the secondary. So how does energy get across? Through the shared magnetic flux in the iron core.
The chain of events: primary AC current → changing B field in the core → changing flux Φ passes through both coils → Faraday's Law induces an EMF in the secondary. The iron core is there only to concentrate and guide the magnetic flux so almost none of it leaks out.
Transformers only work on AC. If you plugged one into a DC battery, the flux would be constant, ΔΦ/Δt = 0, and the secondary would produce zero voltage. This is one of the practical reasons AC beat DC in the "War of the Currents" in the 1890s — Tesla's AC could be easily transformed to high voltages for long-distance transmission; Edison's DC could not.
The turn ratio is the voltage ratio: because each turn of wire sees the same dΦ/dt, the total EMF is (turns)·(EMF per turn). So V_P/V_S = N_P/N_S exactly. Power in ≈ power out (ideal transformer), so currents go the other way: more turns means higher voltage but lower current.
Problem 9 — Step-down transformer
"A 200-watt ideal transformer has a primary voltage of 40 volts and a secondary current of 20 amps. Calculate the input current and output voltage. If there are 80 turns in the primary, how many turns in the secondary?"
"Notice the voltage went down from 40 to 10, so the voltage is decreasing, which means that this is a step-down transformer."
"Because the voltage decreased by a factor of four, the number of turns must also decrease by a factor of four. The current in the secondary coil has to increase by a factor of four."
V_S < V_P → step-down · N_S = N_P·(V_S/V_P) = 80·(10/40) = 20 turns
Conceptual check — "voltage down ⟷ current up"
- Ratio V_P : V_S = 40 : 10 = 4 : 1 → voltage steps down by factor 4
- Because P is conserved: current steps up by factor 4 (5 A → 20 A)
- Turns follow voltage: N_P : N_S = 80 : 20 = 4 : 1
- This is why power lines use step-up transformers: high V, low I → low I²R line losses
A step-down transformer is the everyday device hiding in phone chargers, laptop bricks, and doorbell wiring. Wall outlets in the US deliver ~120 V AC, but a phone battery wants ~5 V DC. The transformer is the first stage: it chops the voltage down to something safe.
The trick of the 4:1 ratio: if the primary has 80 turns and the secondary has 20, then each turn on both sides sees the same flux Φ (they share a common iron core). Faraday says ε per turn = −ΔΦ/Δt — the same number on both sides. So the total voltage just scales with turn count.
Why current goes UP when voltage goes DOWN: energy conservation. Power in = power out (ideally), so V_P·I_P = V_S·I_S. If voltage drops by 4×, current must rise by 4×. This is why the secondary wire is usually thicker — it carries more amps.
Real-world tie-in: the national grid runs at hundreds of thousands of volts precisely because high V means low I, and P_loss = I²R in the wires. Halving the current quarters the loss. Every power pole you see has a transformer stepping down from distribution voltage to your house's 240 V.
Inductance — L = μ₀N²A/ℓ and ε = −L·ΔI/Δt
"If the current is changing there is going to be an induced EMF. The induced EMF is equal to L times the change in current divided by the change in time. L is the inductance, measured in Henrys."
"Anytime the current of a circuit is increasing, the induced current will be opposite to the direction of that current. If the current is decreasing, the induced current will be in the same direction as the main current in the circuit."
"The inductance L is equal to μ₀ times N squared times A divided by L, where μ₀ is the permeability of free space (4π × 10⁻⁷), L is the length of the solenoid, A is the area of the coil, and N represents the number of turns."
"A solenoid consists of 200 loops of wire and has a length of 25 cm. Calculate the inductance of the solenoid if it has a diameter of 8 cm."
"A solenoid has an inductance of 150 millihenries with 300 turns of wire and a circular area of 2.653 square meters. What is the potential energy stored in the inductor when a current of 20 amps passes through it?"
"The energy density is equal to B squared over 2 μ₀. That's how you can find the energy density relative to the magnetic field."
Problem 11 — energy stored in an inductor
- L = 150 mH, N = 300 turns, A = 2.653 m², I = 20 A, ℓ = 2 m
- U = ½·L·I² = ½·(0.150)·(400) = 30 J
- Turns per meter: n = N/ℓ = 300/2 = 150 turns/m
- B = μ₀·n·I = 4π·10⁻⁷·150·20 = 3.77 mT
- Energy density: u = B²/(2μ₀) = 5.66 J/m³
"Whenever a current flows through an inductor, energy is stored in the magnetic field of that inductor, just as when you charge up a capacitor the energy can be stored in the electric field."
An inductor is any coil that generates a magnetic field when current passes through it. When you try to change that current, the coil's own changing flux induces an EMF back on itself — this is called self-induction. The minus sign in ε = −L·ΔI/Δt is just Lenz's Law applied to the coil itself: it fights any change you try to make.
Mental model: think of an inductor as the electrical equivalent of mass. A massive object resists changes in velocity (inertia); an inductor resists changes in current. That's why you can't switch current through an inductor instantly — doing so would require infinite voltage.
Energy stored: U = ½LI² looks exactly like kinetic energy ½mv². This isn't a coincidence — current "flowing" through an inductor carries the same kind of stored kinetic-like energy, but in the magnetic field rather than in moving mass.
Why L = μ₀N²A/ℓ: more turns (N²) means more flux linkage; bigger area (A) means more flux per turn; longer solenoid (ℓ in denominator) means a weaker field per amp. Double the turns → quadruple the inductance.